$(a)\;61.7g\qquad(b)\;16.5g\qquad(c)\;6.15g\qquad(d)\;615g$

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$C_6H_{13}OH\rightarrow C_6H_{12}$

Mole weight of $C_6H_{13}OH=102$

Mole weight of $C_6H_{12}=84$

$102g$ cyclohexanol =$84gC_6H_{12}$

$\therefore$ 100g cyclohexanol =$\large\frac{84\times 100g}{102}$$C_6H_{12}$

Also $\%$ yield is 75%

Weight of $C_6H_{12}=\large\frac{84\times 100\times 75}{100\times 102}$

$\Rightarrow 61.764$

Hence (a) is the correct answer.

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