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If $30ml$ of $H_2$ and $20ml$ of $O_2$ react to form water,what is left at the end of the reaction

$\begin{array}{1 1}(a)\;10ml\;of\;H_2&(b)\;10ml\;of\;O_2\\(c)\;5ml\;of\;o_2&(d)\;5ml\;of\;H_2\end{array}$

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$2H_2+O_2\rightarrow 2H_2O$
$2H_2\Rightarrow$ 2vol
$O_2\Rightarrow$ 1vol
$2H_2O\Rightarrow$ 2Vol
$H_2$ is limiting reagent.
$\therefore$ 30ml $H_2$ would react with $O_2=\large\frac{1}{2}$$3O$
$O_2$ left =$20-15$=5ml
answered Oct 29, 2013 by sreemathi.v

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