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3.0mole NaOH solution has a density of 1.110g/ml.The molarity of the solution is

$(a)\;2.9732\qquad(b)\;3.05\qquad(c)\;3.64\qquad(d)\;3.0504$

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Mole of NaOH=3
Weight of NaOH =$3\times 40g$
$\Rightarrow 120g$
Weight of solvent =1000g
$\therefore$ weight of solution =$1000+(3\times 70)$
$\Rightarrow 1120g$
$\therefore$ Volume of solution =$\large\frac{1120}{1.110}$$ml$
$m=\large\frac{3/1120}{1.110\times 1000}$
$\Rightarrow 2.9732$
Hence (a) is the correct option.
answered Oct 29, 2013 by sreemathi.v
 

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