$(a)\;0.2g\qquad(b)\;0.4g\qquad(c)\;0.6g\qquad(d)\;None\;of\;these$

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$H_2SO_4+2NaOH\rightarrow Na_2SO_4+H_2O$

$\therefore$ millimoles of $H_2SO_4=\large\frac{1}{2}$$\times$ millimoles of NaOH

So, millimoles of NaOH =$2\times M\times V = 2\times 0.5\times 10 = 10$

Or $\large\frac{w}{m_{NaOH}}$$\times 1000=10$

$\Rightarrow \large\frac{w}{40}$$\times 1000=10$

$\Rightarrow w=0.4g$

Hence (b) is the correct answer.

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