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Consider the decomposition reaction of nitroglycerine $4C_3H_5N_3O_9\rightarrow 6N_2+12CO_2+10H_2O+O_2$. If $200g$ nitroglycerine gives 6.55g $O_2$, then percent yield of the reaction is


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$4C_3H_5N_3O_4\longrightarrow 6N_2+12CO_2+10H_2O+O_2$
Molecular mass of $4C_3H_5N_3O_4 = 4\times 227$ g
Molecular mass of $O_2=32g$
The yield of $O_2=\large\frac{32}{908}$$\times 200=7.05g$
$\%$ yield=$\large\frac{6.55}{7.05}$$\times 100= 92.9\%$
Hence (a) is the correct answer.
answered Oct 29, 2013 by sreemathi.v
edited Mar 18, 2014 by mosymeow_1

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