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In Young's double slit experiment, first slit has width four of the second slit. the ratio of the maximum intensity to the minimum intensity in the interference fringe system is :

\[\begin {array} {1 1} (a)\;2:1 & \quad (b)\;4:1 \\ (c)\;9:1 & \quad (d)\;8:1 \end {array}\]
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(c) 9:1
answered Nov 7, 2013 by pady_1

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