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Two solution of a substance (non-electrolyte) are mixed in the following manner,480ml of 0.5M of first solution with 520 ml of 1.2m of second solution.The molarity of final solution is

$\begin{array}{1 1}(a)\;1.20m&(b)\;1.50m\\(c)\;1.344m&(d)\;2.70m\end{array}$

Can you answer this question?

For I $mM=480\times 1.5=720$
For II $mM=520\times 1.2=624$
Total milli-mole=$720+624$
$\Rightarrow 1344$
$m=\large\frac{1344}{480+520}$
$\Rightarrow 1.344m$
Hence (c) is the correct option.
answered Oct 29, 2013