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A rectangular loop of length l and breadth b is placed at distance of x from infinitely long wire carrying current i such that the direction of current is parallel to breadth. If the loop moves away from the current wire in a direction perpendicular to it with a velocity v, the magnitude of the emf in the loop is : ($\mu_o$= permeability of free space)

\[\begin {array} {1 1} (a)\;\frac{\mu _0 iv}{2 \pi x} \bigg(\frac{1+b}{b}\bigg) & \quad (b)\;\frac{\mu_o i^2 v}{4 \pi ^2 x} \log \bigg(\frac{b}{l}\bigg) \\ (c)\;\frac{\mu_0 ilbv}{2 \pi x(l+x)} & \quad (d)\;\frac{\mu_0 ilbv}{2 \pi x (l+x)} \end {array}\]
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$(c)\;\frac{\mu_0 ilbv}{2 \pi x(l+x)}$
answered Nov 7, 2013 by pady_1

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