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Consider a p-n junction as a capacitor, formed with p and n-materials acting as thin metal electron and depletion layer width acting as separation between them. Basing on this , assume that n-p-n transistor is working as an amplifier in CE configuration . If $C_1$ and $C_2$ are the base - emitter and collector- emitter junction capacitances, then:

\[\begin {array} {1 1} (a)\;C_1 > C_2 & \quad (b)\;C_1 < C_2 \\ (c)\;C_1 =C_2 & \quad (d)\;C_1=C_2=0 \end {array}\]
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$(a) C_1 >  C_2$
answered Nov 7, 2013 by pady_1
edited Mar 23, 2014 by meena.p

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