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what is the correct order of spin only magnetic moment (in BM) of $Mn^{2+},Cr^{2+}$ and $ V^{2+}?$

\[\begin {array} {1 1} (a)\;Mn^{2+} > V^{2+} > Cr^{2+} & \quad (b)\;V^{2+} > Cr^{2+} > Mn^{2+} \\ (c)\;Mn^{2+} > Cr^{2+} > V^{2+} & \quad (d)\;Cr^{2+} > V^{2+} > Mn^{2+} \end {array}\]

1 Answer

$(c)\;Mn^{2+} > Cr^{2+} > V^{2+}$
answered Nov 7, 2013 by pady_1
 
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