$(a)\;8\qquad(b)\;5\qquad(c)\;9\qquad(d)\;10$

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$CaCO_3\rightarrow CaO+CO_2$

$CaCO_3\Rightarrow 100kg$

$CaO\Rightarrow 56kg$

Pure lime stone 20kg of 80%$=\large\frac{20\times 80}{100}$

$\Rightarrow 16kg$

$100kg \;CaCO_3$ gives =$56kg\;CaO$

$16kg\;CaCO_3$ give =$\large\frac{56\times 16}{100}$

$\Rightarrow 8.96$

$\approx 9kgCaCO$

Hence (c) is the correct answer.

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