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# Find the number of g-molecules of oxygen in $6.023\times 10^{24}$ CO molecules

$(a)\;5\qquad(b)\;4\qquad(c)\;9\qquad(d)\;10$

1 mole of CO=$\large\frac{1}{2}$mole of O
$6.023\times 10^{24}$ mole of
$CO=\large\frac{1}{2}\times \frac{6.023\times 10^{24}}{6.02\times 10^{23}}$
$\Rightarrow 5$g-mole of CO
Hence (a) is the correct answer.