$\begin{array}{1 1}(a)\;6\times 10^7&(b)\;7.095\times 10^7\\(c)\;5.095\times 10^7&(d)\;9\end{array}$

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$\begin{array}{1 1}(a)\;6\times 10^7&(b)\;7.095\times 10^7\\(c)\;5.095\times 10^7&(d)\;9\end{array}$

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Volume of virus =$\pi r^2l$

$\qquad\qquad\qquad=\large\frac{22}{7}\times \frac{150}{2}\times \frac{150}{2}$$\times 10^{-6}\times 5000\times 10^{-8}$

$\qquad\qquad\qquad=0.884\times 10^{-16}cm^3$

Weight of one virus $=\large\frac{0.884\times 10^{-16}}{0.75}$g

$\Rightarrow 1.178\times 10^{-16}g$

Mol.wt.of.virus=$1.178\times 10^{-16}\times 6.023\times 10^{23}$

$\Rightarrow 7.095\times 10^7$

Hence (b) is the correct answer.

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