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Calculate no of oxalic acid molecules in 100ml of 0.02N oxalic acid

$\begin{array}{1 1}(a)\;6.023\times 10^{10}&(b)\;6.023\times 10^{23}\\(c)\;1.32\times 10^{20}&(d)\;6.023\times 10^{20}\end{array}$

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Normality =0.02
Molarity =$\large\frac{0.02}{2}$
Valency factor =2
$\therefore$Mole of oxalic acid =$\large\frac{0.02}{2}\times \frac{100}{1000}$
Mole =$M\times V(l)$
$\therefore$ No of molecules of oxalic acid =$0.001\times 6.023\times 10^{23}$
$\Rightarrow 6.023\times 10^{20}$
Hence (d) is the correct answer.
answered Oct 30, 2013 by sreemathi.v

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