Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

$5ml$ of a gaseous hydrocarbon was exposed to $30ml$ of $O_2$.The resultant gas,on cooling is found to measure $25\;ml$ of which $10\;ml$ are obsorbed by NaOH and the remainder by pyrogallol.Determine molecular formula of hydrocarbons .All measurement are made at constant pressure and temperature.


Can you answer this question?

1 Answer

0 votes
Let formula of hydrocarbon be $C_aH_b$
$C_aH_b+[a+\large\frac{b}{4}]$$O_2\rightarrow aCO_2+\large\frac{b}{2}$$H_2O(l)$
Also given
Volume absorbed by $NaOHCO_2$ formed =10ml
Volume observed by pyragallol is of $O_2$ left=15ml.
Volume $O_2$ used =30-15=15ml
$\therefore$ Hydrocarbon =$C_2H_4$
Hence (b) is the correct option.
answered Oct 30, 2013 by sreemathi.v
edited Mar 21, 2014 by balaji.thirumalai

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App