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How many milliliter of 0.5M $H_2SO_4$ are needed to dissolve 0.5g of copper II carbonate?

$(a)\;9ml\qquad(b)\;8.097ml\qquad(c)\;8ml\qquad(d)\;9.087ml$

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Equi.wt of $CuCO_3=\large\frac{M}{2}$
Meq of $H_2SO_4$=Meq of $CuCO_3$
$0.5\times 2\times v=0.5\times 2\times 1000$
$v=8.097ml$
Hence (b) is the correct answer.
answered Oct 31, 2013 by sreemathi.v
 

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