logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

What is the strength in g per litre of a solution $H_2SO_4$,12ml of which neutralized 15ml of W/10 of NaOH solution?

$(a)\;7.12g/l\qquad(b)\;3.4g/l\qquad(c)\;6.125g/l\qquad(d)\;7.2g/l$

Can you answer this question?
 
 

1 Answer

0 votes
Meq =$N\times v$ in ml
Meq of $H_2SO_4$=Meq of NaOH
$N\times 12=15\times \large\frac{1}{10}$
$N=\large\frac{15}{10\times 12}$
Strength =$\large\frac{15}{10\times 12}$$\times 49$
$(S=N\times E)$
$\Rightarrow$ 6.125g/l
Hence (c) is the correct answer.
answered Oct 31, 2013 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...