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What is the strength in g per litre of a solution $H_2SO_4$,12ml of which neutralized 15ml of W/10 of NaOH solution?


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Meq =$N\times v$ in ml
Meq of $H_2SO_4$=Meq of NaOH
$N\times 12=15\times \large\frac{1}{10}$
$N=\large\frac{15}{10\times 12}$
Strength =$\large\frac{15}{10\times 12}$$\times 49$
$(S=N\times E)$
$\Rightarrow$ 6.125g/l
Hence (c) is the correct answer.
answered Oct 31, 2013 by sreemathi.v

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