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Calculate the normality of the resulting solution made by adding 2drops(0.1ml) of 0.1N $H_2SO_4$ in 1litre of distilled water.

$(a)\;10^{-8}\qquad(b)\;10^{-6}\qquad(c)\;10^{-5}\qquad(d)\;10^{-4}$

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Meq of solute does not change on dilution.
Meq of $H_2SO_4$(conc)=Meq of $H_2SO_4$(dil)
$0.1\times 0.1=N\times 100$
$N=10^{-5}$
Hence (c) is the correct answer.
answered Oct 31, 2013 by sreemathi.v
 

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