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What volume of a solution of hydrochloric acid containing 73g of acid per litre would suffice for the exact neutralization of sodium hydroxide obtained by allowing 0.46g of metallic sodium to act upon water ?


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$Na+H_2O\rightarrow NaOH+\large\frac{1}{2}$$H_2$
$NaOH+HCl\rightarrow NaCl+H_2O$
Meq of Na=Meq of NaOH formed=Meq of HCl used
$\large\frac{0.46}{23}$$\times 1000=\large\frac{73}{36.5}$$\times V$
Hence (a) is the correct answer.
answered Oct 31, 2013 by sreemathi.v

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