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What volume at NTP of ammonia gas will be required to be passed into 30ml of $NH_2SO_4$ solution to bring down the acid normality to 0.2N

$\begin{array}{1 1}(a)\;537.6ml\qquad(b)\;436ml\qquad(c)\;500ml\qquad(d)\;493.1ml\end{array}$

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Meq of original $H_2SO_4=30\times 1=30$
Meq of $H_2SO_4$ after passing $NH_3=30\times 0.2=6$
Meq of $H_2SO_4$ lost =$30-6=24$
Meq of $NH_3$ passed=Meq of $H_2SO_4$ lost
$\large\frac{w}{17}$$\times 1000=24$
$\therefore$ Volume of $NH_3$ at STP=$\large\frac{22.4\times 0.408}{17}$
$\Rightarrow 0.5376l$
$\Rightarrow 537.6ml$
Hence (a) is the correct answer.
answered Oct 31, 2013 by sreemathi.v

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