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Q)

What is the purity of conc $H_2SO_4$ solution (specific gravity 1.8g/ml),if 5ml of this solution is neutralized by 84.6ml of $2.0N\;NaOH$

$(a)\;93\%\qquad(b)\;91.5\%\qquad(c)\;92.12\%\qquad(d)\;94.6\%$

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A)
Meq of $H_2SO_4$ =Meq of NaOH
$N\times 5=84.6\times 2$
$N=\large\frac{84.6\times 2}{5}$
$\;\;\;\;=33.84eq/l$
Weight of $H_2SO_4$ in 1litre =$33.84\times 49$
$\Rightarrow 1.658g/ml$
$\therefore $ purity =$\large\frac{1.658}{1.8}$$\times 100=92.12\%$
Hence (c) is the correct answer.
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