logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

What is the purity of conc $H_2SO_4$ solution (specific gravity 1.8g/ml),if 5ml of this solution is neutralized by 84.6ml of $2.0N\;NaOH$

$(a)\;93\%\qquad(b)\;91.5\%\qquad(c)\;92.12\%\qquad(d)\;94.6\%$

Can you answer this question?
 
 

1 Answer

0 votes
Meq of $H_2SO_4$ =Meq of NaOH
$N\times 5=84.6\times 2$
$N=\large\frac{84.6\times 2}{5}$
$\;\;\;\;=33.84eq/l$
Weight of $H_2SO_4$ in 1litre =$33.84\times 49$
$\Rightarrow 1.658g/ml$
$\therefore $ purity =$\large\frac{1.658}{1.8}$$\times 100=92.12\%$
Hence (c) is the correct answer.
answered Oct 31, 2013 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...