$H_2SO_4$ is 93% by volume
Wt of $H_2SO_4=93g$
Volume of solution =100ml
Weight of solution =$100\times 1.84$
$\Rightarrow 184g$
Weight of water =184-93=91g
Molality =$\large\frac{Mole}{Wt \;of\; water\; in\; kg}$
$\Rightarrow \large\frac{93}{98\times\large\frac{91}{1000}}$
$\Rightarrow 10.42$
Hence (d) is the correct option.