$(a)\;11.2\qquad(b)\;9.5\qquad(c)\;8\qquad(d)\;10.42$

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$H_2SO_4$ is 93% by volume

Wt of $H_2SO_4=93g$

Volume of solution =100ml

Weight of solution =$100\times 1.84$

$\Rightarrow 184g$

Weight of water =184-93=91g

Molality =$\large\frac{Mole}{Wt \;of\; water\; in\; kg}$

$\Rightarrow \large\frac{93}{98\times\large\frac{91}{1000}}$

$\Rightarrow 10.42$

Hence (d) is the correct option.

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