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A magnet of length 10 cm and magnetic moment $1 Am^2$ is placed along the side AB of an equilateral triangle ABC. If the length of sides AB is 10 cm, the magnetic induction at point C is :

$\begin {array} {1 1} (1)\;10^{-7}T & \quad (2)\;10^{-5}T \\ (3)\;10^{-4}T & \quad (4)\;10^{-9}T \end {array}$

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(3) $ 10^{-4}T$
answered Nov 7, 2013 by pady_1

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