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A uniform chain of length 'l' is placed on a rough table, with its length $ \large\frac{l}{n} ( n > 1)$ hanging over the edge of the table. If the chain just begins to slide off the table by itself, the coefficient of friction between the chain and the table is :

$\begin {array} {1 1} (1)\;\large\frac{1}{n+1} & \quad (2)\;\large\frac{1}{n-1} \\ (3)\;\large\frac{n-1}{n+1} & \quad (4)\;\large\frac{1}{n} \end {array}$

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(2) $\large\frac{1}{n-1}$
answered Nov 7, 2013 by pady_1 1 flag

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