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Home  >>  EAMCET  >>  Physics
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The time period of a simple harmonic motion is 8s. At t=0 , it is at its equilibrium position. The ratio of distances traversed by it in the first and second seconds is :

$\begin {array} {1 1} (1)\;\large\frac{1}{\sqrt 2} & \quad (2)\;\large\frac{1}{\sqrt 2-1} \\ (3)\;\large\frac{1}{\sqrt 3} & \quad (4)\;\large\frac{1}{ 2} \end {array}$

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1 Answer

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(2) $\large\frac{1}{\sqrt 2-1}$
answered Nov 7, 2013 by pady_1
 

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