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At $ 10^{\circ}C$, the value of the density of a fixed mass of an ideal gas divided by its pressure is 'x' . At $110^{\circ}C$ this ratio is :

$\begin {array} {1 1} (1)\;\large\frac{10}{110}x & \quad (2)\;\large\frac{383}{283}x \\ (3)\;\large\frac{110}{10}x & \quad (4)\;\large\frac{283}{383}x \end {array}$

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(4) $ \large\frac{283}{383}x$
answered Nov 7, 2013 by pady_1

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