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In the thermocouple, cold junction is at $0^{\circ}C$, hot junction is at $t^{\circ}C$. The graph drawn between thermo - emf (E) and temperature of the hot junction (t) is represented by the equation , $E=at+bt^2$. If $ a = -224b$ the neutral and the inversion temperatures of the thermocouple respectively, in degree celsius are :

$\begin {array} {1 1} (1)\;224,448 & \quad (2)\;112,224 \\ (3)\;448,224 & \quad (4)\;224,112 \end {array}$

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1 Answer

(2) 112,224
answered Nov 7, 2013 by pady_1
 

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