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$1+\large\frac{2}{4}+\frac{2.5}{4.8}+ \frac{2.5.8}{4.8.12}+\frac{2.5.8.11}{4.8.12.16}+.........$ is equal to :

\[\begin {array} {1 1} (a)\;4^{2/3} & \quad (b)\;\sqrt[3]{16} \\ (c)\;\sqrt [3]{4} & \quad (d)\;4^{3/2} \end {array}\]

1 Answer

$(b)\;\sqrt[3]{16}$
answered Nov 7, 2013 by pady_1
 
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