If $\large\frac{3x+2}{(x+1)(2x^2+3)}=\frac{A}{x+1}+\frac{Bx+C}{2x^2+3},$ then $A+C-B$ is equal to :

$\begin {array} {1 1} (a)\;0 & \quad (b)\;2 \\ (c)\;3 & \quad (d)\;5 \end {array}$

(b) 2
answered Nov 7, 2013 by