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$A= \begin {bmatrix} 1 & 2 & 2 \\ 2 & 1 & 2 \\ 2 & 2 & 1 \end {bmatrix}$ then $A^3-4A^2-6A$ is equal to :

\[\begin {array} {1 1} (a)\;0 & \quad (b)\;A \\ (c)\;-A & \quad (d)\;I \end {array}\]

1 Answer

(c) -A
answered Nov 7, 2013 by pady_1
 

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