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The product of the distinct (2n)th roots of $1+i \sqrt 3$ is equal to :

\[\begin {array} {1 1} (a)\;0 & \quad (b)\;-1-i\sqrt 3 \\ (c)\;1+i \sqrt 3 & \quad (d)\;-1+i \sqrt 3 \end {array}\]
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$(b) -1 -i \sqrt 3$
answered Nov 7, 2013 by pady_1

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