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$cosec 15^{\circ}+ \sec 15^{\circ}$ is equal to :

\[\begin {array} {1 1} (a)\;2 \sqrt 2 & \quad (b)\;\sqrt 6 \\ (c)\;2\sqrt 6 & \quad (d)\;\sqrt 6+\sqrt 2 \end {array}\]

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1 Answer

$(d)\;\sqrt 6+\sqrt 2$
answered Nov 7, 2013 by pady_1
 
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