$(a)\;0.2\qquad(b)\;0.3\qquad(c)\;0.1\qquad(d)\;0.4$

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$N_2O_5\iff 2NO(g)+\large\frac{1}{2}$$O_2$(g)

Initial pressure :

$N_2O_5\Rightarrow 600$

$2NO\Rightarrow 0$

$\large\frac{1}{2}$$O_2\Rightarrow 0$

Final pressure :

$2NO\Rightarrow 600-p$

$2p\Rightarrow 2p$

$\large\frac{1}{2}$$O_2\Rightarrow \large\frac{p}{2}$

Step 2:

$p\alpha$ moles if $V,T$ are constant.

$\therefore 600-p+2p+\large\frac{p}{2}$$=960$

$p=240mm\;Hg$

$\therefore$ Mole fraction Of $N_2O_5$ decomposed $=\large\frac{240}{600}$

$\Rightarrow 0.4$

Hence (d) is the correct answer.

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