$(a)\;2l,1l\qquad(b)\;3l,2l\qquad(c)\;4l,3l\qquad(d)\;2l,3l$

$C_3H_8+5O_2\rightarrow 3CO_2+4H_2O(l)$

$C_4H_{10}+\large\frac{13}{2}$$O_2\rightarrow 4CO_2+5H_2O(l)$

Let $a$ litre of $C_3H_8$ and $b$ litre of $C_4H_{10}$ be present in mixture.

$a+b=3$-------(1)

Volume of $CO_2$ formed =10=$CO_2$ formed by $C_4H_{10}$

$10=3a+4b$------(2)

Solving equation (1) and (2)

$b=1l$

$a=2l$

Hence (a) is the correct answer.

Ask Question

Tag:MathPhyChemBioOther

Take Test

...