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The elevation of an object on a hill is observed from a certain point in the horizontal plane through its base, to be $30^{\circ}$. After walking 120 metres towards it on level ground the elevation is found to be $60^{\circ}$. Then the height of the object (in meters) is :

\[\begin {array} {1 1} (a)\;120 & \quad (b)\;60 \sqrt {3} \\ (c)\;120 \sqrt 3 & \quad (d)\;60 \end {array}\]
Can you answer this question?

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$(b)\;60 \sqrt {3}$
answered Nov 7, 2013 by pady_1

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