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0.22g sample of volatile compound,containing $C,H$ and $Cl$ only on combustion in $O_2$ gave 0.195g $CO_2$ and 0.0804g $H_2O$.If 0.120g of the compound occupied a volume of 37.24ml at $105^{\large\circ}$ and 768mm of pressure,calculate molecular formula of compound.

$(a)\;CH_3Cl\qquad(b)\;C_2H_4Cl_2\qquad(c)\;C_3H_{12}Cl_5\qquad(d)\;CH_3Cl_2$

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