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A number n is chosen at random from $\{1,2,3,4.......,1000\}$. The probability that n is a number that leaves remainder 1 when divided by 7, is :

\[\begin {array} {1 1} (a)\;\frac{71}{500} & \quad (b)\;\frac{143}{1000}\\ (c)\;\frac{72}{500} & \quad (d)\;\frac{71}{1000}\end {array}\]

1 Answer

$(a)\;\frac{71}{500}$
answered Nov 7, 2013 by pady_1
 

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