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Home  >>  CBSE XII  >>  Math  >>  Probability
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Given that E and F are events such that P(E) = 0.6, P(F) = 0.3 and P(E $\cap$ F) = 0.2, find P (E|F) and P(F|E)

$\begin{array}{1 1}P(E/F) = 1/3, P(F/E) = 2/3 \\P(E/F) = 2/3, P(F/E) = 1/3 \\P(E/F) = 1/3, P(F/E) = 1/3 \\P(E/F) = 2/3, P(F/E) = 2/3 \end{array} $

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  • \(\;P(E/F)=\Large \frac{p(E\;\cap\;F)}{P(F)}\)
  • \(\;P(F/E)=\Large \frac{p(E\;\cap\;F)}{P(E)}\)
Given \(P(E)=0.6\;P(F)=0.3\;P(E\cap\;F)=0.2\)
$\Rightarrow$ \(\;P(E/F)=\large \frac{0.2}{0.3}=\frac{2}{3}\)
$\Rightarrow$ \(\;P(F/E)=\large \frac{0.2}{0.6}=\frac{2}{6}=\frac{1}{3}\)
answered Mar 4, 2013 by poojasapani_1
edited Jun 18, 2013 by balaji.thirumalai
 

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