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The lines $x-y-2=0,x+y-4=0$ and $x+3y=6$ meet in the common point

\[\begin {array} {1 1} (a)\;(1,2) & \quad (b)\;(2,2) \\ (c)\;(3,1) & \quad (d)\;(1,1) \end {array}\]

1 Answer

(c) (3,1)
answered Nov 7, 2013 by pady_1
 
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