# The lines $x-y-2=0,x+y-4=0$ and $x+3y=6$ meet in the common point

$\begin {array} {1 1} (a)\;(1,2) & \quad (b)\;(2,2) \\ (c)\;(3,1) & \quad (d)\;(1,1) \end {array}$

(c) (3,1)
answered Nov 7, 2013 by