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The equation of the line passing through the point of intersection of the lines $x-3y+2=0$ and $2x+5y-7=0$ and perpendicular to the line $3x+2y+5=0$ is :
\[\begin {array} {1 1} (a)\;2x-3y+1=0 & \quad (b)\;6x-9y+11=0 \\ (c)\;2x-3y+5=0 & \quad (d)\;3x-2y+1=0 \end {array}\]
jeemain
eamcet
math
2006
q46
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asked
Nov 6, 2013
by
meena.p
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1 Answer
(a) 2x-3y+1=0
answered
Nov 7, 2013
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pady_1
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