Let O be the origin and A be a point on the curve $y^2=4x$. Then the locus of the mid point of OA is :

$\begin {array} {1 1} (a)\;x^2=4y & \quad (b)\;x^2=2y \\ (c)\;y^2=16 x & \quad (d)\;y^2=2x \end {array}$

<div class="clay6-step-odd"><div class="clay6-basic" id="pr10">$(d)\;y^2=2x$</div></div>
answered Nov 7, 2013 by
edited Mar 4, 2014 by meena.p