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EAMCET
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Mathematics
The centroid of the triangle formed by the pair of straight lines $12x^2+20xy+7y^2=0$ and the line $2x-3y+4=0$ is
\[\begin {array} {1 1} (a)\;\bigg(-\frac{7}{3},\frac{7}{3}\bigg) & \quad (b)\;\bigg(-\frac{8}{3},\frac{8}{3}\bigg) \\ (c)\;\bigg(\frac{8}{3},\frac{8}{3}\bigg) & \quad (d)\;\bigg(\frac{4}{3},\frac{4}{3}\bigg) \end {array}\]
jeemain
eamcet
math
2006
q49
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asked
Nov 6, 2013
by
meena.p
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1 Answer
$ (c)\;\bigg(\frac{8}{3},\frac{8}{3}\bigg)$
answered
Nov 7, 2013
by
pady_1
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