$\begin{array}{1 1}(a)\;3.32g,1.68g&(b)\;2.38g,1.28g\\(c)\;1.14g,1g&(d)\;3.2g,2g\end{array}$

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question is wrong it should be 28% as per to the answer

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Step 1:

$Pb(NO_3)_2\rightarrow PbO+2NO_2+\large\frac{1}{2}$$O_2$

$NaNO_3\rightarrow NaNO_2+\large\frac{1}{2}$$O_2$

$a+b=5$------(1)

The loss in weight for 5g mixture $=5\times \large\frac{28}{100}$$=1.4g$

Residue left =$5-1.4g=3.6g$

Step 2:

The residue contains $PbO+NaNO_2$

331g $pb(NO_3)_2$ gives=223g PbO

$a$g $Pb(NO_3)_2$ gives =$\large\frac{223\times a}{331}$g pbo

Similarly 85g $NaNO_3$ gives =$69g$ $NaNO_2$

$b$g $NaNO_3$ gives =$\large\frac{69\times b}{85}$ g $NaNO_2$

$\large\frac{223\times 9}{331}+\large\frac{69}{85}$$\times b=3.6$-----(2)

Step 3:

From (1) & (2) we get

$a=3.32g$

$b=1.68g$

Hence (a) is the correct answer.

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