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EAMCET
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Mathematics
The number of common tangent to the two circles $x^2+y^2-8x+2y=0$ and $x^2+y^2-2x-16y+25=0$ is :
\[\begin {array} {1 1} (a)\;1 & \quad (b)\;2 \\ (c)\;3 & \quad (d)\;4 \end {array}\]
jeemain
eamcet
math
2006
q52
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Nov 6, 2013
by
meena.p
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Nov 7, 2013
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