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If $l_1=\lim \limits _{x \to 2^{+}} (x+[x]). l_2 \lim \limits_{x \to 2^{-}} (2x-[x])$ and $l_3=\lim \limits_{x \to x/2} \large\frac{\cos x}{(x-\pi/2)}$ then :

\[\begin {array} {1 1} (a)\;l_2 < l_1 < l_3 & \quad (b)\;l_2 < l_3 < l_1 \\ (c)\;l_3 < l_2 < l_1 & \quad (d)\;l_1 < l_2 < l_3 \end {array}\]
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1 Answer

$(c)\;l_3 &lt; l_2 &lt; l_1 $
answered Nov 7, 2013 by pady_1
 
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