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The perimeter of a sector is a constant. If its area is to be maximum, the sectorial angle is :
\[\begin {array} {1 1} (a)\;\frac{\pi}{6} & \quad (b)\;\frac{\pi}{4} \\ (c)\;4 & \quad (d)\;2 \end {array}\]
jeemain
eamcet
math
2006
q69
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Nov 6, 2013
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meena.p
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$(d)\;2$
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Nov 7, 2013
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pady_1
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