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If $u= \sin ^{-1} \bigg( \large\frac{x^2+y^2}{x+y}\bigg)$ then $x \large\frac{\partial u}{\partial x}$$+ y \large\frac{\partial u}{\partial y}$ is equal to :

\[\begin {array} {1 1} (a)\;\sin u & \quad (b)\;\tan u \\ (c)\;\cos u & \quad (d)\;\cot u \end {array}\]

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$(b) \tan u$
answered Nov 7, 2013 by pady_1

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