(chatquestion)...spar D (+) glucose reacts with hydroxylamine and yields an oxime. The structure of the oxime would be : CH = NOH CH = NOH %3D %3D H-C- OH НО -С -Н НО -С -Н (1) HO-C-H НО - С -Н (2) H-C-OH Н-С-ОН H-C-OH сHон CH̟OH ČH,OH CH = NOH CH = NOH %3D %3D HO- C-H H-C-OH Н-С-ОН HO- C -H НО - С -Н Н-С-ОН (3) Н-С-ОН Н-С-ОН CH,OH ČH̟OH (@)...(Explain. Plzzz)

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