Browse Questions

# Dividing the interval [0,6] into 6 equal parts and by using trapezoidal rule the value of $\int \limits_0^6 x^3 dx$ is approximately:

$\begin {array} {1 1} (a)\;330 & \quad (b)\;331 \\ (c)\;332 & \quad (d)\;333 \end {array}$

(d) 333