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(chatquestion)...6. mole of KMNO4 mol of ferrous oxalate = Hence, (A) is the correct answer. Illustration 21 What volume of 6 M HNO, is needed to oxidize 8 g of Fe2+ to Fe+, HNO, gets converted to NO? (A) 8 mL (B) 7.936 mL (C) 32 mL (D) 64 mL Solution Meq. of HNO, = Meq. of Fe2+ %3D or 6 x3 xV =- x1000 56 =D7.936 mL n-factor = 3 %3! +5 (NO, → NO) Hence, (B) is the correct answer. 276...(From where does this volume come .......)

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